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$1.44 g r a m$ gram of Titanium (Ti) reacted with excess of $O_{2}$ and produced $x$ gram of non-stoichiometric compound $T i_{1.44} O$ . The value of $x$ will be : $[Ti = 48]$

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$2.77 g$

$3.77 g$

$1.77 g$

$3.0 g$

answer is C.

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Detailed Solution

$1.44 Ti + O \to {Ti}_{1.44} O_{1}$

$1.44 mol Ti produces 1 mol {Ti}_{1.44} O_{1}$

or $1.44 \times 47.8 g Ti produces 84.8 g {Ti}_{1.44} O_{1}$

$1.44 g will produce \frac{1.44 \times 84.8}{1.44 \times 47.8}$

$= 1.77 g$ product

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