1.5 g of CdCl₂ was found to contain 0.9 g of Cd. Calculate the atomic weight of Cd

1.5 g of CdCl₂​ contains 0.9 g of Cd and (1.5 − 0.9 = 0.6) g of chlorine.

∴ 0.6 g of chlorine combines with 0.9 g Cd 
∴ 71 g chlorine will combine with $\frac{0.9}{0.6}\times 71 \mathrm{g}$ of Cd, i.e., 106.5 g of Cd 
∴ Atomic weight of Cd =106.5