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[15]
What will be the power of a pump that can lift $100 kg$ of water stored in a water tank at the height of $19 m in 25 s$ ? ( take $g = 10 m / s$ 2 )

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670 W

480 w

345 w

760 w

answer is D.

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Detailed Solution

760 w

will be the power of a pump that can lift

100 kg

of water stored in a water tank at the height of

19 m in 25 s

.
Given,

Mass = 100 kg

Height =

19 m

Time

t = 25 s

So,

force = m \times g

= 100 \times 10

= 1000 N

Work done = Force \times displacement

Here,the value of displacement given is

19 m .

So,

W = 1000 N \times 19 m

\Rightarrow

W = 19000 J

And we know that

power P = \frac{W}{T}

\Rightarrow P = \frac{19000}{25}

P = 760 W

Thus, the power supplied by the pump is

760 W .

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