16 g of methanol is present in 100 ml of the solution. If the density of the solution is $0.96 \mathrm{g}.{\mathrm{ml}}^{-1}$, the molality of the solution is

Methanol: ${\mathrm{CH}}_3\mathrm{OH}$= 12+3+16+1=32

Given mass= 16g

No. of moles= 16/32= 0.5 moles

Mass of 100ml solution having Density = 0.96g/ml is 96 grams

So mass of solvent =96g- 16g = 80g

Now,  $\mathrm{Molality} =\frac{\mathrm{no}.\mathrm{of} \mathrm{moles} \mathrm{of} \mathrm{solute}}{ \mathrm{mass} \mathrm{of} \mathrm{solvent}\left(\mathrm{kg}\right)}$                 

So, molality= 0.5 x 1000/80 =6.25