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Q.

1.61gm of anhydrous ${ZnSO}_{4}$ was placed in moist air after few days its weight was found to be 2.87gm. What is the molecular formula of hydrated salt?
$[Zn = 65]$

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a

$\begin{aligned} {ZnSO}_{4} \cdot H_{2} O \end{aligned}$

b

${ZnSO}_{4} \cdot 10 H_{2} O$

c

${ZnSO}_{4} \cdot 7 H_{2} O$

d

$\begin{aligned} {ZnSO}_{4} \cdot 3 H_{2} O \end{aligned}$

answer is C.

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Detailed Solution

For hydrate salt, we have,

$\frac{1.61}{161} = 0.01 mol {ZnSO}_{4}$

$n_{H_{2} O} = \frac{2.87 - 1.61}{18} = 0.07 mol H_{2} O$

${ZnSO}_{4} \cdot 7 H_{2} O$ .

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1.61gm of anhydrous ZnSO4 was placed in moist air after few days its weight was found to be 2.87gm. What is the molecular formula of hydrated salt?[Zn=65]