Volume of solution, $\text{V}\text{=}\text{100}\text{mL}$

Density of solution , $\text{d}\text{=}\text{0}\text{.96}\text{g/mL}$

So, weight of solution $\text{W = d}\times \text{V}$

                                          $\text{W = 0}\text{.96}\times \text{100}=96\text{g}$

${\text{W}}_{\text{solvent}}=\text{Total}\text{mass}\text{of}\text{solution }-\text{mass}\text{of solute}$

    ${\text{W}}_{\text{solvent}}=\text{96}-16=80\text{g}$

Molar mass of methanol, $\text{GMW}\text{=}\text{32g/mol}$

Then , molality of solution,

   $m=\frac{w}{\text{GMW}}\times \frac{1000}{\text{weight}\text{of solvent in grams}}$

Therefore, $\text{molality}=\frac{16}{32}\times \frac{1000}{80}=6.25m$