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16g of oxygen and 3g of hydrogen are present in a vessel at $0^{0} C$ and 760mm of Hg pressure. Volume of the vessel is

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11.2 L

5.6 L

44.8 L

22.4 L

answer is B.

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Detailed Solution

$V = \frac{(n_{1} + n_{2}) R T}{P}$

$= \frac{(\frac{3}{2} + \frac{16}{32}) (\frac{22.4}{273}) 273}{1}$

$= (1.5 + 0.5) 22.4$

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