16gm of oxygen and 3gm of hydrogen are present in a vessel at 0°C and 760mm of Hg pressure. Volume of the vessel is

mass of oxygen = 16gm

molecular mass of oxygen gas = 32g/mol

so, no of moles of O₂ gas , n₁ = 16/32 = 0.5

similarly, no of moles of H₂ gas, n₂ = given mass of H₂/molecular mass of H₂

= 3/2 = 1.5

so, total no of moles of gases , n = n1 + n2 = 0.5 + 1.5 = 2

applying formula, PV = nRT

here, P = 760mmHg or ~ 1atm

R = 0.0821 atm.Litre/mol.K

T = 273.15K

so, V = 2 × 0.0821 × 273.15/1

= 44.85123 ≈ 44.8 Litre

hence, volume of the vessel is 44.8 litre.