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17 g of $H_{2} O_{2}$ is present in 100 ml of an aqueous solution, when 10 ml of the aqueous solution is decomposed. The S.T.P volume of oxygen obtained is

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56 ml

1120 ml

560 ml

100 ml

answer is C.

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Detailed Solution

M = \frac{17}{34} \times \frac{1000}{100} = 5 M

$\begin{matrix} 2 M = 22.4 \\ 5 M \to ? \end{matrix}} 56 v o l$

Volume of $O_{2} = 56 \times 10 = 560 m l$

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