17 mg of a hydrocarbon (M.F. C₁₀H₁₆) takes up 8.40mL of the H₂ gas measured at 0°C and 760 mm of Hg. Ozonolysis of the same hydrocarbon yields

The number of double bond/s present in the hydrocarbon is_____

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answer is 3.

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Detailed Solution

$\begin{array}{l} 17 \times 10^{- 3} gm \to 0.374 \times 10^{- 3} mol \\ 17 gm \to 0.374 mol \\ \frac{1}{8} mol \to 0.374 mol \\ 1 mol \to; 3 mol H_{2} \end{array}$

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