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17g of $H_{2} O_{2}$ is present in $100 m l$ an aqueous solution $10 m l$ This decomposition at STP will produce $m l$ of $O_{2}$ at STP?(molar volume at STP = 22.7 L)

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answer is 568.

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Detailed Solution

$\begin{array}{l} 2 H_{2} O_{2} \to O_{2} + 2 H_{2} O \\ 2 m o l H_{2} O_{2} = 1 m o l O \end{array}$

$100 m l a q s o l = 17 g m H_{2} O_{2}$

$10 m l = ?$

$= 10 \times \frac{17}{100} = 1.7 g H_{2} O_{2}$

$1.7 g H_{2} O_{2} = \frac{1.7 \times 22700}{2 \times 34} = 567.5 m L ≅ 568 m l$

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