18 gm of glucose is dissolved in 1 kg of water. If the solution is cooled to  $-0{.2325}^0\mathrm{C},$ then how many gm of ice would separate?

$\Delta T_f=K_{f}m$

$0.2325=1.86m$

$m=0.125$

$\Rightarrow 0.125$ mole Glucose present with 1000 grm water 

$\Rightarrow 18$ grms of Glucose present with _______?

$\Rightarrow \frac{1000}{0.125\times 180}\times 18=800grm$ of water 

$\therefore$weight of ice   initial wt of  $H_{2}O-$ final $=1000-800=200grms$