18 grams of glucose is dissolved in 1 kg of water. If the solution is cooled to 0.2325°C, then how many grams of ice would separate?    

$$\begin{gathered} \Delta {\pi }_f=k_f.m \\ 0.2325=1.86m m=0.125 \end{gathered}$$

0.125 mole glucose present with 1000 gms of $H_{2}O$
18 grms mole glucose  $\to 9$
$\frac{1000}{0.125\times 180}\times 18=800grms\text{ of }{H}_{2}O$ 
Weight of ice formed = Initial weight of  $H_{2}O$ - Final weight of  $H_{2}O$
$\to 1000-800\Rightarrow 200$