1.80 g of solute A was dissolved in 62.5 cm³ of ethanol and freezing point of the solutionwas found to be 155.1 K. The molar mass of solute A is __g mol^-1.
[Given: Freezing point of ethanol is 156.0 K. Density of ethanol is 0.80 g cm^-3.
Freezing point depression constant of ethanol is 2.00 K kg mol^-1]

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answer is 80.

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Detailed Solution

Mass of solvent $= d \times V = 0 .8 \times 62 .5 = 50 g$
$\begin{array}{l} {ΔT}_{f} = k_{f} \times m \\ 0 .9 = 2 [\frac{1 .8 \times 1000}{M_{Solute} \times 50}] \\ M_{Solute} = (\frac{2 \times 1 .8 \times 1000}{0 .9 \times 50}) = 80 g \end{array}$

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