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Q.

1.80 g of solute A was dissolved in 62.5 cm3 of ethanol and freezing point of the solutionwas found to be 155.1 K. The molar mass of solute A is __g mol-1. 
[Given: Freezing point of ethanol is 156.0 K. Density of ethanol is 0.80 g cm-3.
Freezing point depression constant of ethanol is 2.00 K kg mol-1]

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answer is 80.

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Detailed Solution

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Mass of solvent =d×V=0.8×62.5=50g
ΔTf=kf×m0.9=21.8×1000MSolute ×50MSolute =2×1.8×10000.9×50=80g

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