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Q.

180ml of hydrocarbon having a molecular weight 16 diffuses in 1.5min. Under similar conditions time taken by 120ml of $S O_{2}$ to diffuse is ___ min.

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answer is 2.

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Detailed Solution

$\frac{r_{1}}{r_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}$

$\frac{(\frac{180}{1.5})}{(\frac{120}{t})} = \sqrt{\frac{64}{16}} = 2$

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