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19 g of water at 30°C and 5 g of ice at -20°C are mixed together in a calorimeter. What is the final temperature of the mixture? (Given, specific heat of ice = 0.5 cal g^-1 (C⁰)^-1 and latent heat of fusion of ice = 80 cal g^-1)

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5°C

0°C

-5°C

10°C

answer is C.

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Detailed Solution

Heat gained = Heat lost
$\Rightarrow 5 \times 0.5 \times 20 + 5 \times 80 + 5 \times 1 \times (θ - 0) = 19 \times 1 \times (30 - θ) \Rightarrow θ = 5^{o} C$

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