196833×65613×3×21873×3×3×7293×3×3×3×2433×3×3×3×3×3×273×3×3×3×3×3×3×93×3×3×3×3×3×3×3×3196833=393=(39)13=33=27

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$\sqrt[3]{19683} =$

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$9^{2}$

$3^{2}$

$3^{4}$

$27$

answer is C.

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Detailed Solution

$\begin{array}{l} 19683 \\ 3 \times 6561 \\ 3 \times 3 \times 2187 \\ 3 \times 3 \times 3 \times 729 \\ 3 \times 3 \times 3 \times 3 \times 243 \\ 3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 27 \\ 3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 9 \\ 3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3 \\ \sqrt[3]{19683} \\ = \sqrt[3]{3^{9}} \\ = {(3^{9})}^{\frac{1}{3}} \\ = 3^{3} \\ = 27 \end{array}$