1cm³ of water at its boiling point 100°C becomes steam with a volume of 1671cm³. If the atmospheric pressure =1.013 x 10⁵ N/m² & the mechanical equivalent of heat = 4.19 J calorie, then the energy spent in this process in overcoming intermolecular forces is nearly

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*

An Intiative by Sri Chaitanya

zero

500 cal

40 cal

540 cal

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The energy spent in overcoming intermolecular forces is called change in internal energy.

Heat given to system = Latent heat = mL = $(1) (540) = 540 cal$

$\begin{array}{l} ΔQ = ΔU + ΔW \Rightarrow \\ ∴ ΔU = ΔQ - ΔW = 540 - \frac{P (V_{2} - V_{1})}{J} \\ = 540 - \frac{1 .013 \times 10^{5} \times [(1671 - 1) \times 10^{- 6}]}{4.19} \\ = 540 - 40.4 = 500 calories (approx) \end{array}$

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

🔥 Start Your JEE/NEET Prep at Just ₹1999 / month - Limited Offer! Check Now!

Get Expert Academic Guidance – Connect with a Counselor Today!