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1cm³ of water at its boiling point 100°C becomes steam with a volume of 1671cm³. If the atmospheric pressure =1.013 x 10⁵ N/m² & the mechanical equivalent of heat = 4.19 J calorie, then the energy spent in this process in overcoming intermolecular forces is nearly

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zero

500 cal

40 cal

540 cal

answer is C.

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Detailed Solution

The energy spent in overcoming intermolecular forces is called change in internal energy.

Heat given to system = Latent heat = mL = $(1) (540) = 540 cal$

$\begin{array}{l} ΔQ = ΔU + ΔW \Rightarrow \\ ∴ ΔU = ΔQ - ΔW = 540 - \frac{P (V_{2} - V_{1})}{J} \\ = 540 - \frac{1 .013 \times 10^{5} \times [(1671 - 1) \times 10^{- 6}]}{4.19} \\ = 540 - 40.4 = 500 calories (approx) \end{array}$

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