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Q.

(1cosθ)2/7(1+cosθ)9/7=

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a

711tanθ311/7+c

b

711tanθ211/7+c

c

117tanθ211/7+c

d

711cotθ211/7+c

answer is B.

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Detailed Solution

(1cosθ)2/7(1+cosθ)9/7(1cosθ)2/7+1(1+cosθ)9/71(1cosθ) tan2θ29/712sin2θ2  put cotθ/2=t-12cosec2θ2=dt =1t29/7-dt =711t-117+c =711tanθ211/7+c

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