1g of a carbonate (M2CO3) on treatment with excess HCl produces 0.01 mol of CO2. The molar mass of M2CO3 is ______ g mol-1 (Nearest integer)

1 M2CO3 + 2HCl → MCl2 + H2O + CO2no. of moles of CO2 = no. of moles of M2CO30.01 mole of CO2 = 0.01 moles of M2CO30.01 mole = 1g1 mole = 100g

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1g of a carbonate (M₂CO₃) on treatment with excess HCl produces 0.01 mol of CO₂. The molar mass of M₂CO₃ is ______ g mol^-1 (Nearest integer)

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1 M₂CO₃ + 2HCl → MCl₂ + H₂O + CO₂
no. of moles of CO₂= no. of moles of M₂CO₃
0.01 mole of CO₂ = 0.01 moles of M₂CO₃
0.01 mole = 1g
1 mole = 100g

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