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1g of a liquid is converted to vapour at $3 \times 10^{5} P a$ pressure. If 10% of the heat supplied is used for increasing the volume by 1600 $c m^{3}$ during this phase change, then the increase in internal energy in the process will be

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4800 J

4320 J

$4.32 \times 10^{8} J$

432000 J

answer is B.

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Detailed Solution

$\begin{array}{l} d w = P d v \\ = 3 \times 10^{5} \times 1600 \times 10^{- 6} \\ = 480 J \\ 10 % Δ Q = 480 \\ Δ Q = 4800 J \\ Δ v = 90 % Δ Q \\ Δ v = \frac{90}{100} \times 4800 \\ Δ v = 4320 J \end{array}$

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