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Q.

$1 g$ of non-volatile non-electrolyte solute is dissolved in $100 g$ of two different solvent A and B whose ebullioscopic constants are in the ratio of $1 : 5$ . The ratio of the elevation in their boilling points, $\frac{Δ T_{b} (A)}{Δ T_{b} (B)}$ , is

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a

$1 : 5$

b

$10 : 1$

c

$5 : 1$

d

$1 : 0.2$

answer is C.

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Detailed Solution

$\begin{array}{l} Δ T_{b} = K_{b} \times m \\ ∴ \frac{Δ T_{b (A)}}{Δ T_{b (B)}} = \frac{K_{b (A)}}{K_{b (B)}} as m_{A} = m_{B} \\ ∴ \frac{Δ T_{b (A)}}{Δ T_{b (B)}} = \frac{1}{5} . \end{array}$

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1g of non-volatile non-electrolyte solute is dissolved in 100g of two different solvent A and B whose ebullioscopic constants are in the ratio of 1:5. The ratio of the elevation in their boilling points, ΔTb(A)ΔTb(B), is