Q.

 1H1+1H11H2+X+1e0+ energy. The emitted particle is

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a

α–Particle

b

Proton

c

Neutron

d

Neutrino

answer is D.

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Detailed Solution

 1H1+ 1H11H2+X A Z +1e0+ energy
Z=1+1-1-1=0 ; A=1+1-2=0

given particle has zero mass and zero charge. 

Hence, It is neutrino.

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