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Q.

1LN2(g) and 3LH2(g) at 1 bar pressure is allowed to react at constant pressure. The temperature of 100 gm water surrounding reaction vessel rose by 11.4C. Find the magnitude of change in internal energy in joules for the process in reaction vessel. [Specific heat of H2O(l)=4.2J/C/g litre atm =100 J]

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Detailed Solution

In the reaction we have,

N2+3H22NH31L 3L   2LΔH=100×4.2×11.4 =300 JΔH=ΔU+Δ(PV)ΔU=3001(24)×100 =100 J

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