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1M $N H_{4} O H$ and 1MHCl are mixed toa buffer solution of total volume of 300 mL. If pH of the mixture is 9.26 and $p K_{a} (N {H_{4}}^{+}) = 9.26$ then volume ratio of $N H_{4} O H$ and HCl will be:

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3 : 1

2 : 1

1 : 2

1 : 1

answer is C.

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Detailed Solution

If volume of NH₄OH = x ml
Then HCl = (300 - x) ml
pH of mixture = p^Ka of ${NH}_{4}^{+}$
Buffer with [S] = [B]
$1 \times (300 - x) = 1 \times x - (300 - x)$
$x = \frac{600}{3} = 200$ ratio = $\frac{200}{100} = \frac{2}{1}$

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