Q.

1 mole  of an ideal monoatomic gas is confined in a cylinder fitted with a piston as shown in figure. Take mass of the piston is 0.5 Kg, spring constant,K=1000N/m , atmospheric pressure  P0=105N/m2CSA of piston A=50cm2If energy of 50 J has been supplied to system then piston moves up by 5 cm [take g=10m/s2 Initially spring is in its natural position. Mark the correct statement(s).

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a

initial pressure of the gas is 1.01×105N/m2

b

increase in internal energy of the system is  24.625 J

c

for mentioned change, the temperature of gas decreases by 2 k

d

for mentioned change, the temperature of gas increases by 2 k

answer is A, B, C.

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Detailed Solution

Let initial pressure of the gas is P, then

pA=mg+P0AP=P0+mgA=105+0.01×105=1.01×105N/m2

Work done by gas,W=P0dV+mgx+kx22

W=105+50×104×0.05+5×0.05+1000×0.0522=25+0.25+0.125=25.375J From 1 st law, dQ =dU+WdU=5025.375=24.625J

From dU=nCvdTdT=24.6251×3R/2=2 k 

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