1st excitation potential for the H-like (hypothetical sample is 24 V. Then:

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2nd excitation potential of the sample is $\frac{32 \times 8}{9} V$

binding energy of 3rd excited state is 2 eV

ionization energy of the sample is 36 eV

ionization energy of the sample is 32 eV

answer is B, C, D.

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Detailed Solution

The ionization energy;

$(I E) \times [\frac{1}{1^{2}} - \frac{1}{2^{2}}] = 24$

$\Rightarrow I E = 32 eV$ BE 3rd excited state $= \frac{32}{16} = 2 eV$

2nd $I P = 32 \times [\frac{1}{1^{2}} - \frac{1}{3^{2}}] = 32 \times \frac{8}{9} V$

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