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Q.

(1+tan1)(1+tan2)(1+tan3)(1+tan42)(1+tan43)(1+tan44)(1+tan45)=

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a

2

b

222

c

245

d

223

answer is B.

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Detailed Solution

A+B=π4tan(A+B)=tanπ4

tanA+tanB1tanAtanB=1

tanA+tanB=1tanAtanB

tanA+tanB+tanAtanB+1=2

(1+tanA)(1+tanB)=2

(1+tan1)(1+tan2)(1+tan3)(1+tan42)(1+tan43)(1+tan44)(1+tan45)

=2.2.2.2(23 times)

=223

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