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Q.

1 + tanα tanβ2 + tanα - tanβ2=

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a

 tan2α tan2β

b

 sec2α + sec2β

c

 sec2α  sec2β

d

 tan2α + tan2β

answer is C.

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Detailed Solution

  1 + tanα tanβ2 + tanα - tanβ2 =1+tan2α tan2β+2tanα tanβ+tan2α+tan2β-2tanα tanβ =1+tan2α+tan2β+tan2α tan2β =(1+tan2α)(1+tan2β) =sec2α sec2β

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