$1 + \frac{ωx}{1!} + \frac{ω^{2} x^{2}}{2!} + \frac{ω^{3} x^{3}}{3!} \frac{ω^{4} x^{4}}{4!} + \frac{ω^{5} x^{5}}{5!} + \dots . \infty =$

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$e^{x}$

$e^{ωx}$

$e^{ω^{2} x}$

$e^{x^{2}}$

answer is B.

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Detailed Solution

$1 + \frac{ωx}{1!} + \frac{ω^{2} x^{2}}{2!} + \frac{ω^{3} x^{3}}{3!} \frac{ω^{4} x^{4}}{4!} + \frac{ω^{5} x^{5}}{5!} + \dots . \infty = = e^{wx}$

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