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2.35g of bleaching powder were with acetic acid and excess of KI solution ‘x’ is added. The liberated iodine was titrated with 60mL of $\frac{N}{10}$ hypo solution using starch as indicator. Calculate the percentage of available chlorine in the sample of bleaching powder. Given $(\begin{array}{l} {CaOCl}_{2} + 2 {CH}_{3} COOH \to Ca {({CH}_{3} COO)}_{2} + H_{2} O + {Cl}_{2} \\ 2 KI + {Cl}_{2} \to 2 KCl + I_{2} \end{array})$ (rounding to nearest integer)

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answer is 9.

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Detailed Solution

${6m moles of hypo=3 m. moles of I}_{2} = 3 m . Moles of {Cl}_{2}$

${i.e. 0.213 gm Cl}_{2}, % {Cl}_{2} \frac{0.213}{2.35} \times 100 = 9.06$

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