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2, 4 and 6 are the conductance’s of three conductors. When they are joined in parallel, their equivalent conductance will be:

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12 S

(1/12)S

(12/11)S

11/12 S

answer is A.

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Detailed Solution

$R_{1} = 1 / 2 Ω R_{2} = 1 / 4 Ω R_{3} = 1 / 6 Ω$
In parallel
$\begin{array}{l} \frac{1}{Rp} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} = 2 + 4 + 6 = 12 \\ Con G = \frac{1}{R_{i}} = 12 S \end{array}$

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