2 grams of Helium diffuses from a porous plate in 4 min. How many grams of CH4 would diffuse through the same plate in same time under similar conditions?

γ1γ2=M2M1r1r2=W1W2×M2M1×t2t1=M2M1=2W2×164×44=164W2=4gm

2 grams of Helium diffuses from a porous plate in 4 min. How many grams of CH4 would diffuse through the same plate in same time under similar conditions?

γ1γ2=M2M1r1r2=W1W2×M2M1×t2t1=M2M1=2W2×164×44=164W2=4gm

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2 grams of Helium diffuses from a porous plate in 4 min. How many grams of CH₄ would diffuse through the same plate in same time under similar conditions?

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4 g

8 g

2 g

16 g

answer is A.

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Detailed Solution

$\frac{γ_{1}}{γ_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}$

$\begin{aligned} \frac{r_{1}}{r_{2}} = \frac{W_{1}}{W_{2}} \times \frac{M_{2}}{M_{1}} \times \frac{t_{2}}{t_{1}} = \sqrt{\frac{M_{2}}{M_{1}}} \\ = \frac{2}{W_{2}} \times \frac{16}{4} \times \frac{4}{4} = \sqrt{\frac{16}{4}} \\ W_{2} = 4 gm \end{aligned}$