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$\sqrt{2}$ is a polynomial of degree,

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1

2

3

0

answer is D.

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Detailed Solution

Given a polynomial

\sqrt{2}

.
General form of polynomial is given as

a_{n} x^{n} + a_{n - 1} x^{n - 1} + a_{n - 2} x^{n - 2} + \dots + a_{1} x^{1} + a_{0} x^{n}

Degree of the polynomial is the maximum power of x in the given expression.
In polynomial form

\sqrt{2}

is written as f(x)

= \sqrt{2} x^{0}

Since power of x is zero, hence degree of

is 0.
Therefore, option (4) is correct.

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