2 litres of 5 M H₂SO₄ and 4 litres of 1 M NaOH are mixed with each other.The solution is diluted to ten litres. Proton concentration of the resultant mixture is ----- M

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1.8

1.6

0.8

answer is A.

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Detailed Solution

$V_{a} N_{a} = 2 (5) 2; V_{b} N_{b} = 4 (1) 1; V_{a} N_{a} > V_{b} N_{b}; N = {[H]}^{+} = \frac{V_{a} N_{a} - V_{b} N_{b}}{Total volume of the mixture}; N = {[H]}^{+} = \frac{2 (5) 2 - 4 (1) 1}{10} N = 1.6 N;$

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