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2 mole of an ideal gas at $27 ° C$ expands isothermally and reversibly from a volume of 4 litre to 40 litre. The work done (in kJ) by the gas is

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$w = - 11.488 kJ$

$w = - 4.988 kJ$

$w = - 5.736 kJ$

$w = - 28.72 kJ$

answer is B.

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Detailed Solution

$n = 2, t = 300 K, V_{2} = 40 L, V_{1} = 4 L$

$W = - 2.303 n R T \log (\frac{V_{2}}{V_{1}})$

$w = - 11.488 kJ$

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