Q.

2 mole of X and 1 mole of Y are allowed to react in a 2 litre container. When equilibrium is reached. the following reaction occurs 2X(g)+Y(g)Z(g) at 300K If the moles of Z at equilibrium is 0.5 then what is equilibrium constant KC?

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

answer is 4.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

When X reacts with Y the reaction takes place as,

 2X(g)+Y(g)Z(g)  t=021 At eq. 22x 1xx 

Kc=0.52122×122=4

Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
2 mole of X and 1 mole of Y are allowed to react in a 2 litre container. When equilibrium is reached. the following reaction occurs 2X(g)+Y(g)⇌Z(g) at 300K If the moles of Z at equilibrium is 0.5 then what is equilibrium constant KC?