2 moles each of CH3OH & CH3COOH are taken and heated in the presence of conc.H2SO4 so that equilibrium is established. If KC for esterification process is 4, moles of ester present at equilibrium is

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2 moles each of ${CH}_{3} OH & {CH}_{3} COOH$ are taken and heated in the presence of conc. $H_{2} {SO}_{4}$ so that equilibrium is established. If $K_{C}$ for esterification process is 4, moles of ester present at equilibrium is

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1.33

0.67

1.6

0.33

answer is A.

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Detailed Solution

${CH}_{3} COOH + {CH}_{3} OH \to {CH}_{3} {COOCH}_{3} + H_{2} O$

2 2 0 0

Equilibrium: $2 - x 2 - x x x$

$K = \frac{[ester] [H_{2} O]}{[{CH}_{3} OH] [{CH}_{3} COOH]}$

$4 = \frac{x^{2}}{(2 - x)}; x = 1.33$

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