2 moles of a diatomic gas undergoes the process as illustrated in the PV graph from A to B, and then from B to C

Process AB is $P{V}^{-1}$  = constant

The change in temperature in the process from A to B is $\frac{4P_0{V}_0}{R}$

Heat taken by gas in the process A to B is  $24P_0{V}_0$

Total work done by the gas in the process $A\to B\to Cis4P_0{V}_0$