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Q.

2 moles of an ideal gas A is taken in an adiabatic container fitted with a movable frictionless adiabatic piston always operating at 1 atm . The gas A gets converted to gas B as per the reaction :

3A(g)2B(g),ΔH=30kJ/mole

If 75 % of A associates under the given conditions and initial temperature of the vessel was 300 K, then calculate the final temperature of the vessel.
[Given : CP,A(g)=20J/K mole CP,B(g)=30J/K mole  

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answer is 675.

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Detailed Solution

3A(g)2B(g); ΔH=30kJ/mol

t=020t=t2(1α)22x3

1.5  moles of A has associated by 1.5 mole or 15 kJ or energy will be released.

15000=nACPAΔT+nBCPBΔT15000=(20×0.5+30×1)ΔTΔT=375K

Final temperature =300+375=675K

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