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2 moles of liquid A and 3 moles of liquid Bnmakes a solution having a total vapour pressure of 32 torr. The vapour pressures of pure A and pure B are respectively 45 torr and 30 torrrespectively.The described solution is

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shows positive deviation

shows negative deviation

an ideal solution

maximum boiling point azeotrope

answer is B.

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Detailed Solution

$p_{s} = p_{A}^{0} χ_{A} + p_{B}^{0} χ_{B}$

$p_{s} = 45 \times \frac{2}{5} + 30 \times \frac{3}{5} = 36 torr$

Taoults vapour pressure is less than calculated vapour pressure shows positive deviation

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