2 moles of pure KClO3 is decomposed to an extent of 66.6%. How many moles of O2 is released?

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Q.

2 moles of pure KClO₃ is decomposed to an extent of 66.6%. How many moles of O₂ is released?

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answer is 2.

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Detailed Solution

$\begin{array}{l} \frac{2 \times 66 .6}{100} - \frac{2 \times 66 .6}{100} \times \frac{3}{2} \\ = 1 .998 \approx 2 \end{array}$

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