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Q.

20.0 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide and 8.0 g magnesium oxide. What will be the percentage purity of magnesium carbonate in the sample?

 (At.wt.of Mg=24 ) 

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An Intiative by Sri Chaitanya

a

96

b

60

c

84

d

75

answer is C.

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Detailed Solution

MgCO3(s)84 g⟶ΔMgO(s)40 g+CO2(g) 

84 g of MgCO3≡40 g of MgO

∴  20 g of MgCO3≡4084×20=9.52 g of MgO

 Actual yield =8 g of MgO

∴  % purity =89.52×100=84%

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