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Q.

20.0 grams of Magnesium carbonate sample decomposes on heating to give CO2 and 8.0 g magnesium oxide. What will be the percentage purity of Magnesium carbonate in the sample 

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a

75

b

96

c

60

d

84

answer is D.

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Detailed Solution

MgCO3⏟1mole→Mgo⏟1mole+CO2
    84 g of MgCO3 gives 40 g of MgO
∵20 g of MgCO3 →?
=40×2084=9.52g of MgO
Since 8.0 g of MgO is formed, purity of sample =89.52×100=84%

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