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Q.

20.0g of a magnesium carbonate sample decomposes on heating to give carbondioxide and 8.0g magnesium oxide. What will be the percentage purity of magnesium carbonate in the sample ? (Atomic weight of Mg = 24)

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a

96

b

60

c

75

d

84

answer is D.

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Detailed Solution

MgCO3 g→ ΔMgOg+CO2↑

84g -------- 40g

?  ---------  8g

8×8440=16.8 g

Given sample = 20g

16.8g of pure MgCO3 present in given 20g of sample

  ∴ Percentage of purity =  16.820×100=84 %

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