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Q.

20% first order reaction is completed in 50 minutes. Time required for the completion of 60% of the reaction is.......min

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An Intiative by Sri Chaitanya

a

100

b

150

c

262

d

205

answer is D.

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Detailed Solution

                    K20%=K60%

    2.30350log10080=2.303tlog10040

     log10log850=log10log4t

             10.903050=10.6020t

                               t=205min

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