20 mL of 0.02 M K2Cr2O7 solution is used for the titration of 10 mL of Fe2+ solution in the acidic medium.The molarity of Fe2+ solution is ______ × 10-2 M. (Nearest Integer)

Eq. of K2Cr2O7=Eq. of Fe2+⇒ Molarity × volume × n.f) of K2Cr2O7= ( molarity × volume × n.f ) of Fe2+⇒0.02×20×6=M×10×1⇒M=0.24⇒ Molarity =24×10−2

Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

20 mL of 0.02 M K₂Cr₂O₇ solution is used for the titration of 10 mL of Fe²⁺ solution in the acidic medium.
The molarity of Fe²⁺ solution is ______ × 10^-2 M. (Nearest Integer)

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 24.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Eq. of $K_{2} {Cr}_{2} O_{7} =$ Eq. of Fe²⁺

$\begin{array}{l} \Rightarrow (Molarity \times volume \times n.f) of K_{2} {Cr}_{2} O_{7} = \\ (molarity \times volume \times n.f) of {Fe}^{2 +} \\ \Rightarrow 0 .02 \times 20 \times 6 = M \times 10 \times 1 \\ \Rightarrow M = 0 .24 \\ \Rightarrow Molarity = 24 \times 10^{- 2} \end{array}$