20 mL of a sample of H2O2 gives 400 mL of O2 measured at STP. The sample should be labelled as___VOl.

20 mL of H2O2 liberates 400 mL O2 at STP. 1000 mL of H2O2 liberates 400 x 50 mL (= 20 L) of O2 at STP Hence, solution is '20 volume H2O2.

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

20 mL of a sample of $H_{2} O_{2}$ gives 400 mL of O₂ measured at STP. The sample should be labelled as___VOl.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

answer is 20.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

20 mL of $H_{2} O_{2}$ liberates 400 mL O₂ at STP. 1000 mL of $H_{2} O_{2}$ liberates 400 x 50 mL (= 20 L) of O₂ at STP Hence, solution is '20 volume $H_{2} O_{2}$ .

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!