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20 ml of a solution containing $F e S O_{4}$ and $F e_{2} {(S O_{4})}_{3}$ is acidified with conc. $H_{2} S O_{4}$ and reduced with Zn. This solution required 30 ml of $\frac{N}{10} K_{2} C r_{2} O_{7}$ for oxidation. Before reduction with Zn, 20 ml of the same solution required 20 ml of $\frac{N}{10} K_{2} C r_{2} O_{7}$ for oxidation. The molarities of $F e S O_{4}$ and $F e_{2} {(S O_{4})}_{3}$ respectively are

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0.1 , 0.05

0.05, 0.025

0.1 , 0.1

0.1 , 0.025

answer is D.

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Detailed Solution

number of moles of $F e S O_{4} = a$
number of moles of $F e_{2} {(S O_{4})}_{3} = b$
$a + 2 b = 3, a = 2$

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