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20 mL of methane is completely burnt using 50 mL of oxygen. The volume of the gas left after cooling to room temperature is

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40 mL

80 mL

60 mL

30 mL

answer is D.

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Detailed Solution

$C H_{4} (g) + 2 O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l)$

given 20ml 50 ml
Vol. 20ml 40 ml 20ml

involved

_____________________
10ml 20ml
-------------------------------------------------

Total Vol. 10 ml (unreacted $O_{2}) + 20 ml$ (vol.of ${CO}_{2})$

= 30 ml

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